64m^2+8m-2=0

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Solution for 64m^2+8m-2=0 equation:



64m^2+8m-2=0
a = 64; b = 8; c = -2;
Δ = b2-4ac
Δ = 82-4·64·(-2)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-24}{2*64}=\frac{-32}{128} =-1/4 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+24}{2*64}=\frac{16}{128} =1/8 $

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